In this lesson, we are only going to deal with square roots only which is a specific type of radical expression with an index of \color{red}2. 19The process of determining an equivalent radical expression with a rational denominator. The radicand in the denominator determines the factors that you need to use to rationalize it. Sometimes, we will find the need to reduce, or cancel, after rationalizing the denominator. Rationalize the denominator: $$\frac { \sqrt { 2 } } { \sqrt { 5 x } }$$. Finally, add all the products in all four grids, and simplify to get the final answer. We are just applying the distributive property of multiplication. (x+y)(x−y)=x2−xy+xy−y2=x−y. In this example, multiply by $$1$$ in the form $$\frac { \sqrt { 5 x } } { \sqrt { 5 x } }$$. Typically, the first step involving the application of the commutative property is not shown. When two terms involving square roots appear in the denominator, we can rationalize it using a very special technique. That is, numbers outside the radical multiply together, and numbers inside the radical multiply together. This technique involves multiplying the numerator and the denominator of the fraction by the conjugate of the denominator. Note that multiplying by the same factor in the denominator does not rationalize it. Then simplify and combine all like radicals. }\\ & = 15 \sqrt { 2 x ^ { 2 } } - 5 \sqrt { 4 x ^ { 2 } } \quad\quad\quad\quad\:\:\:\color{Cerulean}{Simplify.} Simplifying Radical Expressions Multiply: $$3 \sqrt { 6 } \cdot 5 \sqrt { 2 }$$. Example 7: Simplify by multiplying two binomials with radical terms. In the next a few examples, we will use the Distributive Property to multiply expressions with radicals. \begin{aligned} \frac { 1 } { \sqrt { 5 } - \sqrt { 3 } } & = \frac { 1 } { ( \sqrt { 5 } - \sqrt { 3 } ) } \color{Cerulean}{\frac { ( \sqrt { 5 } + \sqrt { 3 } ) } { ( \sqrt { 5 } + \sqrt { 3 } ) } \:\:Multiply \:numerator\:and\:denominator\:by\:the\:conjugate\:of\:the\:denominator.} }\\ & = \frac { 3 a \sqrt { 4 \cdot 3 a b} } { 6 ab } \\ & = \frac { 6 a \sqrt { 3 a b } } { b }\quad\quad\:\:\color{Cerulean}{Cancel.} root(n)axxroot(n)b=root(n)(ab) Example 1 (a) sqrt5sqrt2 Answer Some of the worksheets for this concept are Multiplying radical, Multiplying radical expressions, Multiply the radicals, Multiplying dividing rational expressions, Grade 9 simplifying radical expressions, Plainfield north high school, Radical workshop index or root radicand, Simplifying radicals 020316. The "index" is the very small number written just to the left of the uppermost line in the radical symbol. In this example, the conjugate of the denominator is \(\sqrt { 5 } + \sqrt { 3 }. Recall that multiplying a radical expression by its conjugate produces a rational number. Multiplying a two-term radical expression involving square roots by its conjugate results in a rational expression. Example 6: Simplify by multiplying two binomials with radical terms. Notice that the middle two terms cancel each other out. Research and discuss some of the reasons why it is a common practice to rationalize the denominator. Notice that $$b$$ does not cancel in this example. The LibreTexts libraries are Powered by MindTouch® and are supported by the Department of Education Open Textbook Pilot Project, the UC Davis Office of the Provost, the UC Davis Library, the California State University Affordable Learning Solutions Program, and Merlot. $$\frac { 5 \sqrt { 6 \pi } } { 2 \pi }$$ centimeters; $$3.45$$ centimeters. Multiplying Radical Expressions. Give the exact answer and the approximate answer rounded to the nearest hundredth. Check it out! $$\sqrt { 6 } + \sqrt { 14 } - \sqrt { 15 } - \sqrt { 35 }$$, 49. Divide: $$\frac { \sqrt { 50 x ^ { 6 } y ^ { 4} } } { \sqrt { 8 x ^ { 3 } y } }$$. Similar to Example 3, we are going to distribute the number outside the parenthesis to the numbers inside. But make sure to multiply the numbers only if their “locations” are the same. ), 43. Students learn to multiply radicals by multiplying the numbers that are outside the radicals together, and multiplying the numbers that are inside the radicals together. Just like in our previous example, let’s apply the FOIL method to simplify the product of two binomials. Do not cancel factors inside a radical with those that are outside. The radical in the denominator is equivalent to $$\sqrt [ 3 ] { 5 ^ { 2 } }$$. Given real numbers $$\sqrt [ n ] { A }$$ and $$\sqrt [ n ] { B }$$, $$\sqrt [ n ] { A } \cdot \sqrt [ n ] { B } = \sqrt [ n ] { A \cdot B }$$\. We use cookies to give you the best experience on our website. From this point, simplify as usual. \\ & = - 15 \sqrt [ 3 ] { 4 ^ { 3 } y ^ { 3 } }\quad\color{Cerulean}{Simplify.} Let’s try an example. If a radical expression has two terms in the denominator involving square roots, then rationalize it by multiplying the numerator and denominator by the conjugate of the denominator. \begin{aligned} 3 \sqrt { 6 } \cdot 5 \sqrt { 2 } & = \color{Cerulean}{3 \cdot 5}\color{black}{ \cdot}\color{OliveGreen}{ \sqrt { 6 } \cdot \sqrt { 2} }\quad\color{Cerulean}{Multiplication\:is\:commutative.} \\ &= \frac { \sqrt { 20 } - \sqrt { 60 } } { 2 - 6 } \quad\quad\quad\quad\quad\quad\:\:\:\color{Cerulean}{Simplify.} When multiplying radicals, as this exercise does, one does not generally put a "times" symbol between the radicals. \(\frac { \sqrt { 75 } } { \sqrt { 3 } }, $$\frac { \sqrt { 360 } } { \sqrt { 10 } }$$, $$\frac { \sqrt { 72 } } { \sqrt { 75 } }$$, $$\frac { \sqrt { 90 } } { \sqrt { 98 } }$$, $$\frac { \sqrt { 90 x ^ { 5 } } } { \sqrt { 2 x } }$$, $$\frac { \sqrt { 96 y ^ { 3 } } } { \sqrt { 3 y } }$$, $$\frac { \sqrt { 162 x ^ { 7 } y ^ { 5 } } } { \sqrt { 2 x y } }$$, $$\frac { \sqrt { 363 x ^ { 4 } y ^ { 9 } } } { \sqrt { 3 x y } }$$, $$\frac { \sqrt [ 3 ] { 16 a ^ { 5 } b ^ { 2 } } } { \sqrt [ 3 ] { 2 a ^ { 2 } b ^ { 2 } } }$$, $$\frac { \sqrt [ 3 ] { 192 a ^ { 2 } b ^ { 7 } } } { \sqrt [ 3 ] { 2 a ^ { 2 } b ^ { 2 } } }$$, $$\frac { \sqrt { 2 } } { \sqrt { 3 } }$$, $$\frac { \sqrt { 3 } } { \sqrt { 7 } }$$, $$\frac { \sqrt { 3 } - \sqrt { 5 } } { \sqrt { 3 } }$$, $$\frac { \sqrt { 6 } - \sqrt { 2 } } { \sqrt { 2 } }$$, $$\frac { 3 b ^ { 2 } } { 2 \sqrt { 3 a b } }$$, $$\frac { 1 } { \sqrt [ 3 ] { 3 y ^ { 2 } } }$$, $$\frac { 9 x \sqrt { 2 } } { \sqrt [ 3 ] { 9 x y ^ { 2 } } }$$, $$\frac { 5 y ^ { 2 } \sqrt [ 3 ] { x } } { \sqrt [ 3 ] { 5 x ^ { 2 } y } }$$, $$\frac { 3 a } { 2 \sqrt [ 3 ] { 3 a ^ { 2 } b ^ { 2 } } }$$, $$\frac { 25 n } { 3 \sqrt [ 3 ] { 25 m ^ { 2 } n } }$$, $$\frac { 3 } { \sqrt [ 5 ] { 27 x ^ { 2 } y } }$$, $$\frac { 2 } { \sqrt [ 5 ] { 16 x y ^ { 2 } } }$$, $$\frac { a b } { \sqrt [ 5 ] { 9 a ^ { 3 } b } }$$, $$\frac { a b c } { \sqrt [ 5 ] { a b ^ { 2 } c ^ { 3 } } }$$, $$\sqrt [ 5 ] { \frac { 3 x } { 8 y ^ { 2 } z } }$$, $$\sqrt [ 5 ] { \frac { 4 x y ^ { 2 } } { 9 x ^ { 3 } y z ^ { 4 } } }$$, $$\frac { 1 } { \sqrt { 5 } + \sqrt { 3 } }$$, $$\frac { 1 } { \sqrt { 7 } - \sqrt { 2 } }$$, $$\frac { \sqrt { 3 } } { \sqrt { 3 } + \sqrt { 6 } }$$, $$\frac { \sqrt { 5 } } { \sqrt { 5 } + \sqrt { 15 } }$$, $$\frac { - 2 \sqrt { 2 } } { 4 - 3 \sqrt { 2 } }$$, $$\frac { \sqrt { 3 } + \sqrt { 5 } } { \sqrt { 3 } - \sqrt { 5 } }$$, $$\frac { \sqrt { 10 } - \sqrt { 2 } } { \sqrt { 10 } + \sqrt { 2 } }$$, $$\frac { 2 \sqrt { 3 } - 3 \sqrt { 2 } } { 4 \sqrt { 3 } + \sqrt { 2 } }$$, $$\frac { 6 \sqrt { 5 } + 2 } { 2 \sqrt { 5 } - \sqrt { 2 } }$$, $$\frac { x - y } { \sqrt { x } + \sqrt { y } }$$, $$\frac { x - y } { \sqrt { x } - \sqrt { y } }$$, $$\frac { x + \sqrt { y } } { x - \sqrt { y } }$$, $$\frac { x - \sqrt { y } } { x + \sqrt { y } }$$, $$\frac { \sqrt { a } - \sqrt { b } } { \sqrt { a } + \sqrt { b } }$$, $$\frac { \sqrt { a b } + \sqrt { 2 } } { \sqrt { a b } - \sqrt { 2 } }$$, $$\frac { \sqrt { x } } { 5 - 2 \sqrt { x } }$$, $$\frac { \sqrt { x } + \sqrt { 2 y } } { \sqrt { 2 x } - \sqrt { y } }$$, $$\frac { \sqrt { 3 x } - \sqrt { y } } { \sqrt { x } + \sqrt { 3 y } }$$, $$\frac { \sqrt { 2 x + 1 } } { \sqrt { 2 x + 1 } - 1 }$$, $$\frac { \sqrt { x + 1 } } { 1 - \sqrt { x + 1 } }$$, $$\frac { \sqrt { x + 1 } + \sqrt { x - 1 } } { \sqrt { x + 1 } - \sqrt { x - 1 } }$$, $$\frac { \sqrt { 2 x + 3 } - \sqrt { 2 x - 3 } } { \sqrt { 2 x + 3 } + \sqrt { 2 x - 3 } }$$. $$\frac { 5 \sqrt { x } + 2 x } { 25 - 4 x }$$, 47. 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